Given below are half cell reactions: `` MnO _{4}^{-}+8 H ^{+}+5 e ^{-} \rightarrow Mn ^{2+}+4 H _{2} O `` `` E _{ Mn ^{2+} / MnO _{4}^{-}}^{\circ}=-1.510\, V `` `` \frac{1}{2} O _{2}+2 H ^{+}+2 e ^{-} \rightarrow H _{2} O , `` `` E _{ O _{2} / H _{2} O }^{\circ}=+1.223 \,V `` Will the permanganate ion, `` MnO _{4}^{-} `` liberate `` O _{2} `` from water in the presence of an acid ?
(A)No, because `` E _{\text {cell }}^{\circ}=-2.733 \,V ``

(B)Yes, because `` E _{\text {cell }}^{\circ}=+0.287\, V ``
(C)No, because `` E _{\text {cell }}^{\circ}=-0.287 \,V ``
(D)Yes, because `` E _{\text {cell }}^{\circ}=+2.733 \,V ``