NEET-XII-Chemistry

c2022 year:2022

with Solutions - page 3
  • #46
    The order of energy absorbed which is responsible for the color of complexes (A) `` \left[ Ni \left( H _{2} O \right)_{2}( en )_{2}\right]^{2+} `` (B) `` \left[ Ni \left( H _{2} O \right)_{4}( en )\right]^{2+} `` and (C) `` \left[ Ni ( en )_{3}\right]^{2+} ``
    (A)(B) > (A) > (C)
    (B)(A) > (B) > (C)
    (C)(C) > (B) > (A)

    (D)(C) > (A) > (B)
    digAnsr:   D
    Ans : (A) `` \left[ Ni \left( H _{2} O \right)_{2}( en )_{2}\right]^{2+} ``
    (B) `` \left[ Ni \left( H _{2} O \right)_{4}( en )\right]^{2+} ``
    (C) `` \left[ Ni ( en )_{3}\right]^{2+} ``
    en is SFL (strong field ligand)
    As the number of en (strong ligand) increase splitting also increases.
    So, `` \Delta_{0} `` increases.
    i.e. maximum energy will be absorbed in case of option `` C `` .
    So the order is `` C >A >B ``