NEET-XII-Chemistry
c2022 year:2022
- #24In one molal solution that contains `` 0.5 `` mole of a solute, there is
(A) `` 1000\, g `` of solvent
(B) `` 500 \, mL `` of solvent
(C) `` 500\, g `` of solvent
(D) `` 100\, mL `` of solventdigAnsr: CAns : `` m =\frac{\text { Moles of solute }}{\text { Weight of solvent }( g )} \times 1000 ``
`` 1=\frac{0.5}{\text { Weight of solvent }( g )} \times 1000 ``
Weight of solvent `` ( g )=500\, g ``